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29=-16t^2+29t+6
We move all terms to the left:
29-(-16t^2+29t+6)=0
We get rid of parentheses
16t^2-29t-6+29=0
We add all the numbers together, and all the variables
16t^2-29t+23=0
a = 16; b = -29; c = +23;
Δ = b2-4ac
Δ = -292-4·16·23
Δ = -631
Delta is less than zero, so there is no solution for the equation
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